C# initialize list with multiple values
Web64. This is probably a pretty obvious question, but how would I go about creating a List that has multiple parameters without creating a class. Example: var list = new List (); list.Add ("hello", 1); I normally would use a class like so: public class MyClass { public String myString {get; set;} public Int32 myInt32 {get; set;} } WebIn the above example, List primeNumbers = new List(); creates a list of int type. In the same way, cities and bigCities are string type list. You can then add elements in a list using the Add() method or the collection-initializer syntax.. You can also add elements of the custom classes using the collection-initializer syntax.
C# initialize list with multiple values
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WebSep 15, 2024 · You can use object initializers to initialize type objects in a declarative manner without explicitly invoking a constructor for the type. The following examples … WebMay 9, 2024 · One is to create and initialize the inner most lists first, then add them to the parents as you create them: // Create child lists IList fareInfoRef = IList (); // And add some items IList taxInfo = new IList (); // And add some items // Create the parent and add children Airpricinginfo airPricingInfo ...
WebJul 29, 2024 · You need to use the static constructor to initialize the static list like this: public class ApiLanguages { public static List AllowedLanguages { get; set; } static ApiLanguages () { AllowedLanguages = new List (); AllowedLanguages.Add ("de"); //... } } You can make your constructor static as well, but I prefer lazy loading. WebFeb 1, 2012 · From C# 3, you can use collection initializers to construct a List and populate it using a single expression. The following example constructs a Human and its ContactNumbers: var human = new Human(1, "Address", "Name") { ContactNumbers = new List() { new ContactNumber(1), new ContactNumber(2), new …
WebNov 2, 2024 · 2. Specifying List size and initializing all values. Another way to initialize a list is by assigning a particular value to all the elements of the list. In this method, we pass a desired size for the list and the value to be stored for all the elements of that size. WebDec 12, 2024 · That should be okay. From the spec, section 17.2: An expression E is an attribute-argument-expression if all of the following statements are true:. The type of E is an attribute parameter type (§17.1.3). At compile-time, the value of E can be resolved to one of the following:
WebIn 2.0 you must use it like this: List optionList = new List () { "AdditionalCardPersonAdressType", /* rest of elements */ };. Note the () here: new …
WebJul 26, 2016 · And keep in mind, as mentioned in 1., that list's Capacity is not the same as Count: var list = new List (10); // this will print 10 Console.WriteLine ("Capacity is {0}", list.Capacity); // but this will throw an exception list [0] = ""; Most likely, however, this method is unnecessary and there is a better way to accomplish what you're ... soler pharmacyWebNote that the dictionary collection initialization { { key1, value1 }, { key2, value2 } } depends on the Dictionary's Add (TKey, TValue) method. You can't use this syntax with the list because it lacks that method, but you could make a subclass with the method: public class KeyValueList : List> { public ... smack their lipssmack the jackWebJul 24, 2014 · 7. List has no specific method to do this. The loop is your best option. However, you can make it more efficient at runtime, by initializing the list with an initial capacity: var myList = new List (100); When using this constructor, the list will internally allocate an array of 100 elements. If you use the default constructor, it will ... solers theoryWebMay 27, 2024 · #Note: for reference type it results in a list of 5 references to same instance. E.g.: var l = Enumerable.Repeat(new SomeRefType(),5).ToList(); will create single instance of SomeRefType & populate list with 5 references to this instance. – smack the lipsWebJun 17, 2024 · This is a C# newbie question. Consider the following array declaration and initialization: // This declare the array and initialize it with the default values double[] MyArray = new double[3]; Somewhere in my code, I initialize the array as follows: MyArray[0] = 1d; MyArray[1] = 2d; MyArray[2] = 3d; soler panels on roof 24 ft x 40 ft priceWebAll the information is in the existing answers, but I personally wished for a concise summary, so here's an attempt at it; the commands use int variables for brevity, but they apply analogously to any type, including string.. To declare multiple variables and:. either: initialize them with separate values: int i = 0, j = 1; // declare and initialize each, single … solers number of employees